tan(135+a)/cotan(315-a)+sin(270-a)/sec a
Matematika
Putritan25
Pertanyaan
tan(135+a)/cotan(315-a)+sin(270-a)/sec a
1 Jawaban
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1. Jawaban Anonyme
tan (135 + a)
= (tan 135 + tan a)/(1 - tan 135 tan a)
= (-1 + tan a)/(1 + tan a)
= (tan a - 1)/(1 + tan a)
cot (315 - a)
= 1/tan (315 - a)
= (1 + tan 315 tan a)/(tan 315 - tan a)
= (1 - tan a)/(-1 - tan a)
= (tan a - 1)/(1 + tan a)
sin (270 - a)
= -cos a
sec a = 1/cos a
•••
...soal...
= 1 + (-cos a)/(1/cos a)
= 1 - cos² a
= sin² a ✔