Matematika

Pertanyaan

tan(135+a)/cotan(315-a)+sin(270-a)/sec a

1 Jawaban

  • tan (135 + a)
    = (tan 135 + tan a)/(1 - tan 135 tan a)
    = (-1 + tan a)/(1 + tan a)
    = (tan a - 1)/(1 + tan a)

    cot (315 - a)
    = 1/tan (315 - a)
    = (1 + tan 315 tan a)/(tan 315 - tan a)
    = (1 - tan a)/(-1 - tan a)
    = (tan a - 1)/(1 + tan a)

    sin (270 - a)
    = -cos a

    sec a = 1/cos a

    •••
    ...soal...
    = 1 + (-cos a)/(1/cos a)
    = 1 - cos² a
    = sin² a ✔

Pertanyaan Lainnya