Matematika

Pertanyaan

U3 4 u9 256 maka u15

1 Jawaban

  • Un = a × r⁽ⁿ⁻¹⁾

    U₃ = 4
    a × r⁽³⁻¹⁾ = 4
    a.r² = 4

    U₉ = 256
    a × r⁽⁹⁻¹⁾ = 256
    a.r⁸ = 256

    Mencari nilai "r"
    U₉ / U₃ = 256 / 4
    (a.r⁸) / (a.r²) = 64
    r⁽⁸⁻²⁾ = 64
    r⁶ = 2⁶ ............. aˣ = bˣ ⇒ a = ˣ√bˣ ⇒ a = b⁽ˣ/ˣ⁾ ⇒ a = b
    r = 2

    Mencari nilai "a"
    a × r² = 4
    a × (2²) = 4
    a × 4 = 4
    a = 4/4
    a = 1

    Mencari U₁₅
    Un = a × r⁽ⁿ⁻¹⁾
    U₁₅ = (1) × (2)¹⁴
    U₁₅ = (2)¹⁴
    U₁₅ = 16.384

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