Diketahui f'(x)=6x²+2 dan f(-1)=4.nilai f(0)=
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Pertanyaan
Diketahui f'(x)=6x²+2 dan f(-1)=4.nilai f(0)=
1 Jawaban
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1. Jawaban bayusadewo
f' (x) = 6x^2+2
dy/dx = 6x^2+2
dy = 6x^2+2 dx
y = integral 6x^2+2 dx
y = 2x^3+2x
f(-1) = 2(-1)^3 +2(-1) = -4
f(0) =0