Matematika

Pertanyaan

jika 9 pangkat n=4,maka 4 dikali 3 pangkat n+1 -27 pangkat n=

1 Jawaban

  • Jika
    [tex] {9}^{n} = 4 \\ ( { {3}^{2} })^{n} = ({ {2}^{2}) }^{1} \\ ({ {3}^{n} )}^{2} = ( { {2}^{1} )}^{2} \\ {3}^{n} = {2}^{1} \\ {3}^{n} = 2[/tex]
    Maka
    [tex]4 . {3}^{n + 1} - {27}^{n} \\ =4. {3}^{n} . {3}^{1} - ({ {3}^{3} })^{n} \\ = 4.3. {3}^{n} - ({ {3}^{n} })^{3} \\ = 12. {3}^{n} - ({ {3}^{n} })^{3} \\ = 12.2 \: - ( {2})^{3} \\ = 24 - 8 \\ = 16 [/tex]
    Semoga dapat dipahami

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