tolong jawab ya no 13
Fisika
Najmayas
Pertanyaan
tolong jawab ya no 13
1 Jawaban
-
1. Jawaban MuhammadSamman18
[tex] \frac{3ab}{2c} \div \frac{9b ^{2} }{4ac} \\ = \frac{3ab}{2c} \times \frac{4ac}{9b ^{2} } \\ = \frac{3ab}{2} \times \frac{4a}{9b ^{2} } \\ = 3ab \times \frac{2a}{9b^{2} } \\ = ab \times \frac{2a}{3b^{2} } \\ = a \times \frac{2a}{3b} \\ = \frac{2a ^{2} }{3b} [/tex]
semoga membantu