Nilai dari 1 integral -1 (2x2-4x+4) dx=

∫x^n dx = 1/(n + 1) . x^(n + 1) + C

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∫(2x² - 4x + 4) dx [1...-1]
= 2x³/3 - 4x²/2 + 4x
= 2/3 x³ - 2x² + 4x
= 2/3 (1³ - (-1)³) - 2(1² - (-1)²) + 4(1 - (-1))
= 4/3 - 0 + 8
= 9 1/3