log(X-2)+log(X+1)=log(7-X) dengan caranya

[tex]log(a) + log(b) = log(ab) \\ log(x - 2) + log(x + 1) = log(7 - x) \\ log(x - 2)(x + 1) = log(7 - x) \\ log( {x}^{2} + x - 2x - 2) = log(7 - x) \\ log( {x}^{2} - x - 2) = log(7 - x) \\ {x}^{2} - x - 2 = 7 - x \\ {x}^{2} - x - 2 - 7 + x = 0 \\ {x}^{2} - 9 = 0 \\ {x}^{2} = 9 \\ x = \sqrt{9} \\ x = 3[/tex]
Semoga dapat dipahami