Tentukan grafien dari : a. 5(×+y) = 0 b. 2(6×+y)-5× c. 1/2× + 1/4y = 1/2 d. (×-5)3 = 2y

[tex]c. \: \frac{1}{2} x + \frac{1}{4} y = \frac{1}{2} \\ \frac{1}{2} x + \frac{1}{4} y - \frac{1}{2} = 0 \\ m = \frac{ - \frac{1}{2} }{ \frac{1}{4} } = - \frac{1}{2} \div \frac{1}{4} \\ = - \frac{1}{2} \times \frac{4}{1} = \frac{ - 4}{2} = - 2[/tex]
[tex] d. {(x - 5)}^{3} = 2y \\ {(x - 5)}^{3} - 2y = 0 \\ (x - 5)(x - 5)(x - 5) - 2y = 0 \\ ({x}^{2} - 5x - 5x + 25)(x - 5) - 2y = 0 \\ ({x}^{2} - 10x + 25)(x - 5) - 2y = 0 \\ {x}^{3} - 5 {x}^{2} - 10 {x}^{2} + 50x + 25x - 125 - 2y = 0 \\ {x}^{3} - 15 {x}^{2} + 75x - 125 - 2y = 0 \\ {x}^{3} - 15 {x}^{2} + 75x - 2y - 125 = 0 \\ \\ m = \frac{ - 75}{ - 2} = \frac{75}{2} [/tex]
Ini jawaban yg c dan d nya..