Matematika

Pertanyaan

Tolong yah nomer 4 dan 5:)))
Tolong yah nomer 4 dan 5:)))

1 Jawaban

  • U1 + U2 + U3 = 210
    a + ar + ar^2 = 210...(1)
    U6 + U7 + U8 = 6720
    ar^5 + ar^6 + ar^7 = 6720
    r^5 ( a + ar + ar^2) = 6720
    r^5 (210) = 6720
    r^5 = 6720/210
    r^5 = 32
    r^5 = 2^5
    r = 2
    dari (1), a + ar + ar^2 = 210
    a + a.2 + a.2^2 = 210
    a + 2a + 4a = 210
    7a = 210
    a = 210/7 = 30
    jumlah 2 suku pertama,
    S2 = U1 + U2
    = a + ar
    = 30 + 30.2
    = 30 +60
    = 90
    Jadi jumlah 2 suku pertama = 90
    5) n = 7
    a = 5
    U7 = 320
    ar^6 = 320
    5r^6 = 320
    r^6 = 64
    r^6 = 2^6
    r = 2
    Sn = a { r^n - 1)/(r - 1)
    S7 = 5 { 2^7 - 1)/(2-1)
    = 5 (128 -1)/1
    = 5 . 127
    = 635
    jadi panjang kawat = 635 cm