Matematika

Pertanyaan

lim x mendekati 3 2x^2 -3x -9 per x.sin (2x - 6)

1 Jawaban

  • lim [x-->3] (2x² - 3x - 9/x sin 2(x - 3)
    = lim [x-->3] (2x + 3)(x - 3) / x . 2 sin (x - 3) cos (x - 3)
    = lim [x-->] (2x + 3)/2x cos (x - 3)
    = (2.3 + 3)/2.3 cos 0
    = 9/6
    = 3/2

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