(F○g)(×)=10×-8 dan g(×)=2×+4 maka f-1(×)

8(f o g) (x) = 10x - 8
f(g(x) ) = 10x - 8
f (2x + 4) = 10x - 8

misal p = 2x + 4 maka x = (p - 4) / 2

f(p) = (10(p - 4) / 2) - 8
f(p) = 5(p - 4) - 8
f(p) = 5p - 20 - 8
f(p) = 5p - 28
f(x) = 5x - 28

untuk invers
f(x) = y
y = 5x - 28
x = (y + 28) / 5
f(x)-¹ = x
f(x)-¹ = (x + 28) / 5

Bab Fungsi Komposisi
Matematika SMA Kelas X

(fog) (x) = 10x - 8
f(2x + 4) = 5 (2x + 4) - 28
f(x) = 5x - 28

f(x) = 5x - 28
y = 5x - 28
5x = y + 28
x = (y + 28)/5
f^(-1) (x) = (x + 28)/5