Jika f(x) = (2x + 1 per 2x) pangkat 2 . Maka f' (2) adalah..

Fungsi

f(x) = ( 2x + (2x)^-1 )²
= 4x² + 2(2x)/2x + (2x)^-2
= 4x² + 2 + x^-2/4
f'(x)
= 8x + (1/4)(-2)x^-2+1
= 8x - 2x^-1
= 8x - 1/2x

f(x) = (2x + 1/2x)²

f'-1 (2x + 1/2x)² = x
f^-1 (2) = x

2x + 1/2x = 2
Kalikan 2x
4x² - 4x + 1 = 0
(2x - 1)² = 0
2x - 1 = 0
x = 1/2

f^-1 (2) = x = 1/2 ✔