Ini cara nya gimana tolong di jawab soal nya penting.

³log (9^x + 18) = 2 + x
9^x + 18 = 3^(2 + x)
(3²)^x + 18 = 3² . 3^x
(3^x)² + 18 = 9.3^x
misalkan 3^x = p
p² + 18 = 9p
p² - 9p + 18 = 0
(p - 6)(p - 3) = 0
p - 6 = 0
p = 6
3^x = 6
x = ³log 6 = ³log (3.2)
= ³log 3 + ³log 2
= 1 + ³log 2
p - 3 = 0
p = 3
3^x = 3¹
x = 1
jadi x1 = 1 + ³log 2
x2 = 1
maka
x1 + x2 = 1 + ³log 2 + 1 = 2 + ³log 2