Matematika

Pertanyaan

tentukan kpk dan fpb dari bentuk berikut! a.4a²b.6abc²,dan 8ab³c b.8xy²z,16xyz²,dan 18x²yz

2 Jawaban

  • 4a²b = 2² × a² × b
    6abc² = 2 × 3 × a × b × c²
    8ab³c = 2³ × a × b³ × c
    fpb = 2 × a × b = 2ab
    kpk = 2³ × 3 × a² × b³ × c² = 24a²b²c²

    8xy²z = 2³ × x × y² × z
    16xyz² = 2⁴ × x × y × z²
    18x²yz = 2 × 3² × x² × y × z
    fpb = 2 × x × y x z = 2xyz
    kpk = 2⁴ × 3² × x² × y² × z² = 144x²y²z²
  • Jawabannya:
    - 4a^2b= 2^2. a^2. b
    - 6abc^2= 2. 3. a. b. c^2
    - 8ab^3c= 2^3. a. b^3. c
    FPB= 2. a. b= 2ab
    KPK= 2^3. 3. a^2. b^3. c^2= 24a^2b^2c^2

    - 8xy^2= 2^3. x. y^2. z
    - 16xyz^2= 2^4. x. y. z^2
    - 10x^2yz= 2. 3^2. x^2. y. z
    FPB= 2. x. y. z= 2xyz
    KPK= 2^4. 3^2. x^2. y^2. z^2= 144x^2y^2z^2

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