penyelesain dari sistem persamaan linier tiga variabel 2x-y+z=6 , x-3y+z=-2 , x+2y-z=3

2x-y+z=6 ....... (1)
x-3y+z=-2 ...... (2)
x+2y-z=3 ....... (3)
# eliminasi z ( 1 dan 2 )
2x-y+z=6
x-3y+z=-2 _
__________
x + 2y =8 ........ (4)

# eliminasi z ( 2dan 3)
x-3y+z=-2
x+2y-z=3 +
_________
2x-y = 1 .......... (5)

#eliminasi (4 dan 5 )
x+2y=8 (×2)........ 2x+4y=16
2x-y=1 (×1 )........ 2x-y = 1 _
__________
5y = 15
y = 15 / 5
y = 3
# substitusi y ( 5 )
2x-y =1
2x-(3)=1
2x = 1+ 3
x = 4/2
x = 2

# substitusi x dan y ke ( 1 )
2x-y+z=6
2 (2)-(3)+z=6
4-3+z = 6
z = 6 -1
z = 5

Hp { 2, 3, dan 5 }

thanks.