Garis d melalui titik (-40,-50) dan tegak lurus garis 10x+3y =12.

10x+3y=12
3y=-10x+12
y=-10/3x+12/3
y=-10/3x+4
m1=-10/3
m2=3/10
(-40,-50)
y-b = m(x-a)
y-(-50) = 3/10(x-(-40))
10(y+50)= 3(x+40)
10y+500=3x+120
-3x+10y=120-500
-3x+10y=-380