Matematika

Pertanyaan

1. 3^log(x^2-4x-3)=2
2. x^log (6x^2-8x)=3
3. 3^log (x^2+1)=3^log5
4. log (2x+1) = log (x+9)

1 Jawaban

  • nomor 1
    3^log(x^2-4x-3)=2
    3^log(x^2-4x-3)=3^log9
    x^2-4x-3 = 9
    x^2-4x-12 = 0
    (x-6)(x+2) = 0
    x = 6 atau x = -2

    nomor 2
     x^log (6x^2-8x)=3
    x^3 = 6x^2-8x
    x^3 - 6x^2+8x = 0
    x(x^2 - 6x+8x) = 0
    (x-0)(x-4)(x-2)
    x = 0, x = 4, atau x= 2

    nomor 3
    3^log (x^2+1)=3^log5
    x^2+1 = 5
    x^2-4 = 0
    (x-2)(x+2) = 0
    x=-2 atau x = 2

    nomor 4 
    log (2x+1) = log (x+9)
    2x+1 = x+9
    x=8

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