Persmaan dua variabel dengan metode subsitusi A.2x+3y=5 dan 4x-y=3 B.4x-y=3 dan 2/3x+5=-1 C.2x+10y dan 5x-9y=1

a) 4x - y = 3
- y = - 4x + 3
y = 4x - 3
subtitusi
2x + 3y = 5
2x + 3(4x - 3) = 5
2x + 12x - 9 = 5
14x = 5 + 9
14x = 14
x = 1
subtitusi
y = 4x - 3
y = 4(1) - 3
y = 4 - 3
y = 1
hp = ( 1,1 )

b) 4x - y = 3
- y = - 4x + 3
y = 4x - 3
subtitusi
⅔ x + 5y = - 1
⅔ x + 5(4x - 3) = - 1
⅔ x + 20x - 15 = - 1
⅔ x + 20x = - 1 + 15
⅔ x + 20x = 14 ( dikali 3)
2x + 60x = 42
62x = 42
x = 42/62
x = 21/31
subtitusi
y = 4x - 3
y = 4(21/31) - 3
y = 82/31 - 93/3
y = - 11/31
hp = ( 21/31 , - 11/31 )