persamaan garis yg melalui titik k(-1,-6) dan L(-4,-3) adalah...

menentukan persamaan garis

(y - y₁) ÷ (y₂ - y₁) = (x - x₁) ÷ (x₂ - x₁)
(y + 6) ÷ (-3 + 6) = (x + 1) ÷ (-4 + 1)
(y + 6) ÷ 3 = (x + 1) ÷ (-3)
-3 (y + 6) = 3 (x + 1)
-(y + 6) = (x + 1)
-y - 6 = x + 1
x + y + 1 + 6 = 0
x + y + 7 = 0

y = -x+5
moga-moga bener.................................................................................