tentukan matriks x dari persamaan a. |2 -3 | | 8 | |3 1 | x = | -1 |
Matematika
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Pertanyaan
tentukan matriks x dari persamaan
a. |2 -3 | | 8 |
|3 1 | x = | -1 |
a. |2 -3 | | 8 |
|3 1 | x = | -1 |
1 Jawaban
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1. Jawaban AnugerahRamot
Matriks
Kelas X
[tex] \left(\begin{array}{cc}2 & -3 \\ 3 & 1 \end{array}\right) X = \left(\begin{array}{cc}8 \\ -1 \end{array}\right) [/tex]
[tex] \left(\begin{array}{cc}2 & -3 \\ 3 & 1 \end{array}\right)^{-1} = \frac{1}{11}\left(\begin{array}{cc}1 & 3 \\ -3 & 2 \end{array}\right) \\
= \left(\begin{array}{cc}\frac{1}{11} & \frac{3}{11} \\ - \frac{3}{11} & \frac{2}{11} \end{array}\right) \\ [/tex]
[tex] X = \left(\begin{array}{cc}2 & -3 \\ 3 & 1 \end{array}\right)^{-1} \left(\begin{array}{cc}8 \\ -1 \end{array}\right) \\
X = \left(\begin{array}{cc}\frac{1}{11} & \frac{3}{11} \\ - \frac{3}{11} & \frac{2}{11} \end{array}\right) \left(\begin{array}{cc}8 \\ -1 \end{array}\right) \\
X = \left(\begin{array}{cc}\frac{5}{11} \\ - \frac{26}{11}\end{array}\right) [/tex]