Balok ABCD EFGH jika panjang AB=12cm BC=9CM dan HB=17cm maka panjang AE adalah...dibantu plisss

[tex] HB^{2} = AE^{2} + AB^{2} + BC^{2} \\ 17^{2} = AE^{2} + 12^{2} + 9^{2} \\ 289= AE^{2} +144+81 \\ AE^{2} =289-225 \\ AE^{2} =64 \\ AE= \sqrt{64}=8 [/tex]