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jawab

[tex]P\,=\, \left[\begin{array}{cc}z&-1\\3&z-1\end{array}\right] [/tex]

det P = z (z - 1) - 3(-1)
det P = z² - z + 3

[tex]Q\,=\, \left[\begin{array}{ccc}1&0&-3\\2&z&-6\\1&3&z-5\end{array}\right] [/tex]

[tex]det\,Q\,= 1[(z)(z-5)\,-3(-6)]+ 0[(2)(z-5)-1(-6)- 3[2(3)- 1(z)][/tex]

[tex] det\,Q\,=z^2 - 5z +18 + 0 - 3(6 - z) \\ det\,Q\,=z^2 -5z +18 - 18 + 3z \\ det\.Q\,=z^2 - 2z [/tex]

Det P = Det Q
z² - z + 3 = z^2 - 2z
z = -3