Tentukan penyelesaian SPLDV dari 1. 2x+y=2 (1)dan x+5y=1 (2) 2. 2x +y=3(1) dan x-3y=5 (2)

1) Eliminasi
2x + y = 2 | ×10 | 20x + 10y = 20
x + 5y = 1 | ×2 | 2x + 10y = 2
(10y di coret, sisanya dikurang)
18x = 18
x = 18/18
x = 1
Substitusi
2x + y = 2
2(1) + y = 2
2 + y = 2
y = 2/2
y = 1

2) Eliminasi
2x + y = 3 | ×1 | 2x + y = 3
x - 3y = 5 | ×2 | 2x - 6y = 10
(2x dicoret, sisanya dikurang)
7y = 7
y = 7/7
y = 1
Substitusi
2x + y = 3
2x + 1 = 3
2x = 3 - 1 = 2
x = 2/2
x = 1