diketahui f(x) = ax+b dengan f (3) =1 dan f(1) = -1 berapa nilai f(2)-f(-2)

f(x) = ax+b
f(3) =3a+b = 1
f(1) =1a +b =-1
--------------------- -
2a =2
a = 1
dimasukkan ke persamaan
f(1) =1a +b =-1
=> 1.1 +b =-1
=> b=-1-1
=> b= -2


f(2) = ax+b
=> 1.2 + (-2)
=> 2 - 2 = 0

f(-2) = ax+b
=> 1.(-2) + (-2)
=> -2 - 2 = -4

f(2)-f(-2)= 0 -(-4)
=4